Question

12 Calculate the extension of a copper wire of length
1.00 m and diameter 1.00 mm when a tensile force
of 10 N is applied to the end of the wire. (Young
modulus E of copper = 130 GPa.)​

Answer 1

Answer:

I don't now

sorry mmmmmmmmmmm

Answer 2

Answer:

9.8 x 10^-5

Explanation:

L = 1m

F = 10N

r = 5x10^-8 m^2

y = 130 x 10^9

stress = F/A

strain =  L/L   hence, y = stress/strain

Y = F x L/A x L

Area = 75 x 10^-8   (7.8 x 10^-7 m^2)

130 x 10^9 = 10 / 7.8 x 10^-7 x 130 x 10^9

Hence  L = 10^1 + 7 - 9 / 7.8 x 130

L = 10^-1 / 1014 = 0.1 / 1014  => 9.8 x 10^-5