Question

12.
Calculate the number of moles and the volume
STP :
0 1.6 g of oxygen​

Answer 1

Answer:

0.05 moles and 1.12 litres

Explanation:

molar mass of o2=32.

given mass=1.6

no of moles=given mass/molar mass

no of moles=1.6/32=0.05 moles

volume of one mole=22.4 litres.

0.05 moles=22.4×0.05=1.12 litres.

Answer 2

Answer:

0.05 moles

1.12 L

Explanation:

Molar mass of O₂ = 32 g.

Hence, number of moles of oxygen in 1.6 gram of oxygen = 1.6/32 =  0.05

Hence, volume occupied = no. of moles × 22.4 = 0.05 × 22.4 = 1.12 litre

(Concept - Volume occupied by one mole of gas at STP is 22.4 litre.)