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12. Calculate the weight of silver deposited when 15 ampere of ce
min through AgNO, solution. At wt of Ag = 108)
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Answered by
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Explanation:
Given:
Molar Mass of Ag = 108 g/mol
1F=96500 Cmol−1
Reaction at cathode = Ag+e−→Ag(s)
w=Zlt
Where, w = Mass deposited at cathode
Z = electrochemical constant
I = current
t = time
Now I = 2amp
t=15 min=15×60=900 seconds
Z = Eq. wt of substance /96500=108/96500
So,
w=96500108×900×2
= 2.015g
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Answer:
refer the attachment
Explanation:
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