Question

12. Calculate the work done in moving a charge of 5 coulombs from a point at a potential of 210 volts to another point at 240 volts those who knows proper step only they'll answer !​

Answer 1

Answer :-

Required work done is 150 J .

Explanation :-

We have :-

→ Potential at 1st point = 210 V

→ Potential and 2nd point = 240 V

→ Charge = 5 C

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Potential difference between the two points (V) will be :-

= (240 - 210) V

= 30 V

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Now, we know that :-

W = QV

Where :-

• W is the work done.

• Q is the charge.

• V is potential difference.

Substituting values, we get :-

⇒ W = 5 × 30

⇒ W = 150 J

Answer 2

Answer:

Given :-

• A change of 5 coulombs from a point at a potential of 210 volts to another point at 240 volts.

To Find :-

• What is the work done.

Formula Used :-

$\clubsuit$ Work Done Formula :

$\longrightarrow \sf\boxed{\bold{\pink{W =\: QV}}}$

where,

• W = Work Done
• Q = Charge
• V = Potential Difference

Solution :-

First, we have to find the potential difference :

Given :

$\bigstar$ Potential Difference at first point = 210 V

$\bigstar$ Potential Difference at second point = 240 V

Then,

$\implies \sf Potential\: Difference =\: 240\: V - 210\: V$

$\implies \sf\bold{\green{Potential\: Difference =\: 30\: V}}$

Now, we have to find the work done :

Given :

$\bigstar$ Charge = 5 Coulombs

$\bigstar$ Potential Difference = 30 V

According to the question by using the formula we get,

$\longrightarrow \sf W =\: 5 \times 30$

$\longrightarrow \sf\bold{\red{W =\: 150\: J}}$

$\therefore$ The work done is 150 J .