Question

12. Chin and Chan start from two cities 88 km apart towards each other. Speed of their bikes is
in ratio of 5:6., Chan's bike is performing at 90 km/h. After how much time will they cross
each other?
(a)28 min
(b) 32 min
(c)37 min
(d) 45 min​

Answer 1

Answer:

b)32 min

Step-by-step explanation:

Let both the speeds be 5x and 6x

the second speed is 6x i.e., 90

6x = 90

x = 90/6

x = 15

6x = 90.....S1

then we can find 5x

x = 15

5x = 15*5

5x = 75.....S2

when the two trains or bikes are coming towards each other then the total speed is addition of got S1 and S2

therefore totla speed is (90+75)= 165 speed = distance / time

hence time = distance / speed

distance = 88

time = 88 / 165

time = 0.53

as this answer is in hr we want it in mins so multiply 0.53 by 60

0.53 × 60 = mins

31.99 = mins

31.99 = 32 mins

Answer 2

Answer:

(B) 32min

Step-by-step explanation:

From the question,

The distance between them is 88km

The ratio between Chin and Chan = 5:6

If the Chan's bike is performing at 90km/h

To calculate the performance of Chin's Speed

Since 6 = 90

5 = x

Then cross multiply

Then 6x = 90(5) = 450

Therefore x = 75km/h

This implies that the speed of Chin is 75hk/h

Now to find the equivalent speed (V) of the duo, we are to sum them together

Eq. Speed (V) = 90 + 75 = 165km/h

Since, their distance S = 88km

Time (T) = Distance/Eq. Speed = S/V

T = 88/165 = 0.533h

But in order to convert it to minute

T = 0.533(60) = 31.998 ≅ 32min