Question

12. Consider the following reaction sequence:
CaCl2(aq) + CO2(g) + H2O → CaCO3(s) + 2HCl(aq)
CaCO3(s) heat CaO(s) + H2O(g).
If the percentage yield of the 1st step is 80% and
that of the 2nd step is 75%, then what is the
expected overall percentage yield for producing
CaO from CaCl ?
(1) 50%
(2) 70%
(3) 55%
(4) 60%​

Answer 1

Answer:

(4) 60%​

Explanation:

Percentage yield of reaction 1 is 80% . It means that the formation of $CaCO_3$ is 80% of $CaCl_2$

Percentage yield of reaction 2 is 75% . It means that the formation of $CaO$ is 75% of $CaCO_3$

Thus, formation from $CaCl_2$ to $CaO$, the percentage yield is:

% yield = $\frac {80}{100}\times \frac {75}{100}\times 100$ = 60%

Option 4 is correct.