12. Construct two isosceles triangles ABC and ABE with common base AB = 5 cm, AC = BC = 3 cm and AE = BE = 7 cm. Name the shape so formed.
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Given ABC is an isosceles right angled triangle with ∠B=90
∘
⟹AB=BC
By Pythagoras theorem, AC
2
=AB
2
+BC
2
AC
2
=2AB
2
--------(i) (as AB=BC)
Given that, ABE≅ADC
We know, Ratios of areas of similar triangles is equal to ratio of squares of their corresponding sides.
Hence,
Area of △ACD
Area of △ABE
=
AC
2
AB
2
Area of △ACD
Area of △ABE
=
2AB
2
AB
2
-------from(i)
Area of △ACD
Area of △ABE
=
2
1
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1
Answer:
THIS IS WHAT I GOT FROM MAKING THIS.
I DONT KNOW ITS CORRECT FIGURE OR NOT
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