12 costhetha- 16 sin thetha = 0 find 2sin thetha + cos thetha
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Answer:
Answer is 10sinθ/3
Step-by-step explanation:
12cosθ - 16sinθ = 0 (given)
To find =
2sinθ + cosθ -------- i)
Solution:
cosθ = 16sinθ/12
cosθ = 4sinθ/3
substitute in i)
= 2sinθ + (4sinθ)/3
= (6sinθ + 4sinθ) / 3 (by LCM)
= 10sinθ/3
Answer is 10sinθ/3
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