12 defective pens are mixed with 120 good ones. One pen is taken out at random from this lot. Calculate the probability that the pen taken out is not defective.
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Answered by
8
Answer:
Step-by-step explanation:
No. of good pens = 120
No. of defective pens = 12
Total No. of pens = 120 + 12 = 132
No. of out comes favourable to not a defective pens = 132 - 12 = 120
∴ p(e) =
= 0.90
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3
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