Question

12. Divide 32 into four parts which are the four terms of an AP such that the
product of the first and the fourth terms is to the product of the second
and the third terms as 7:15.
[CBSE 2014​

Answer 1

Answer:

$8-3/\sqrt{2} , 8-1/\sqrt{2},8+1/\sqrt{2},8+3/\sqrt{2}$

Step-by-step explanation:

let the terms of AP be a-3d, a-d, a+d, a+3d.

now, sum of all terms=4a=32         i.e. a=8

now, {a(-3d)*(a+3d)}:{(a-d)*(a+d)}=(a-9d^2):(a-d^2)=7:15

on solving above equation, d=$1/\sqrt{2}$

hence put the values of a and d in all the terms.