Question

12. Divide a line segment of length 30 cm into three parts whose ratio is 5:7:3.​

Answer 1

Answer:

10, 14, 6

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Step-by-step explanation:

to solve this, we will use the following steps:

we know that a ratio stays the same as long as you multiply or divide ALL the terms in it with the SAME number.

we will assume that all three terms are multiplied by an unknown value, n.

so, now, the three parts of the line segment are 5n, 7n and 3n.

this means that the sum of all these terms is 30.

this makes the given equation which we can solve.

5n+7n+3n = 30.

now, we solve it in the following steps.

15n = 30.

n = 30/15

n = 2/1

n = 2.

now, we multiply each of the terms with 2, so that the sum makes 30.

so,

5n = 10

7n = 14

3n = 6.

Answer 2

Given:-

• Length of line segment is 30 cm.
• Ratio of line segment is 5:7:3.

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To find:-

• Length of three parts.

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Solution:-

Here,

• Length = 30 cm
• Ratio = 5:7:3

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Let,

• the first part be 5x.
• the second part be 7x.
• the third part be 3x.

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According to the question

→ 5:7:3 = 30

→ 5x + 7x + 3x = 30

→ 12x + 3x = 30

→ 15x = 30

→ x = 30/15

→ x = 2

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Therefore,

• First part = 5x = 5 × 2 = 10
• Second part = 7x = 7 × 2 = 14
• Third part = 3x = 3 × 2 = 6

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Hence,

• the length of first part is 10 cm, length of second part is 14 cm and length of third part is 6 cm.