Question

12 drops of oelic acid having a radius 2 mm forms the circular film in water of radius 4 cm, Calculate thickness of drop​

Answer 1

Answer:

So easy!!

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Answer 2

Hello Dear.

We know, the Shape of the one Drops is Spherical in shape.

Radius of the Drop = 1.4 mm.

 = 0.14 cm.

∴ Volume of the Drop = (4/3)π r³

     = (4/3) × (22/7) × (0.14)³

     = (241472 × 10⁻⁶) ÷ 21

Volume of the 10 Drop of 1/400 cm³ Concentration/cm³ 

= Volume of 1 Drop × 10 × 1/400 

= (241472 × 10⁻⁶) ÷ (21 × 400)

= (603.68 × 10⁻⁶) ÷ 21

= 603.68/21000000  cm³

Radius of the Circular Film = 10 cm.

∵ Area = π r²

            = (22/7) × (10)²

            = 2200/7 cm²

Now,

Molecular Size or Thickness = Volume of one drop/Area of the Film.

   = 

   =  (603.68 × 7) ÷ (21 ×  10⁶ × 2200)

   =  (4225.76 × 10⁻⁸) ÷ 462

   = 9.1467 × 10⁻⁸ cm

Thus, the the Thickness or the Molecular size of drop of Oliec Acid is 9.1467× 10⁻⁸ cm.

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