Question

12) Eight years ago, A was 4 times as old as B. After 8 years A will be
twice as old as B. What are their ages respectively?​

Answer 1

Answer:

Let the present ages of A and B be x and y

Eight years ago,

Age of A = (x-8)

Age of B = (y-8)

Therefore,

(x-8) = 4(y-8)

x-8 = 4y - 32

x - 4y = -32 +8

x - 4y = -24 ---(i)

After eight years,

Age of A = (x+8)

Age of B = (y+8)

Therefore ,

(x+8) = 2(y+8)

x+8 = 2y + 16

x-2y = 16-8

x-2y=8 ---(ii)

x-4y=-24 ---(i)

x-2y=8 ------(ii)

(i)-(ii)

-4y-(-2y) = -24-8

-4y+2y=-32

-2y=-32

y=16

Putting y=16 in (i) we get,

x-4*16=-24

x-64=-24

x=-24+64

x=40

Therefore , x=40 , y=16

SO , THE PRESENT AGES OF A AND B ARE 40 AND 16 YEARS RESPECTIVELY.

PLEASE MARK ME AS THE BRAINLIEST

Step-by-step explanation: