Question

12. Equation of path of any projectile is y**(1-x). If
g=10m/s, then find:
(1) Projectile angle (ii) Projection velocity (ii)
Horizontal range (iv) Maximum height​

Answer 1

Explanation:

Range =1m

Time of flight =5sec

Maximum height =0.25 m

Angle of projectile =

Answer :

B

Solution :

y=x(1-x) compare with

<br> So

, angle projection is

<br> and R=1m <br>

<br>

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