12. Evaluate (999)3 using suitable identity.
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=> ( a - b )³ = a³ - b³ - 3ab ( a - b )
999 = (1000 – 1)
∴ 999³ = (1000 – 1)³
= (1000)³ – 1³ – 3 x 1000 x 1 (1000 – 1)
999³ = 1000000000 – 1 – 3000 (1000 - 1)
999³ = 1000000000 – 1 – 3000000 + 3000
=>1000003000 – 3000001
999³ = 997002999
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