Question

12.Expand i) (2x+y+3z)^2
ii) (102)^3
ii) (3a+4b)^3

Answer 1

Answer:

1: 4x+2y+6z

2: 204

3:9a+12b

Step-by-step explanation:

please mark as brainliest n thank me

Answer 2

Answer:

Given :-

12. Expand 1) (2x + y + 3z)²

2) (102)³

3) (3a + 4b)³

Solution :-

1) (2x + y + 3z)²

➭ (2x)² + (y)² + (3z)² + 2 × 2x × y + 2 × y × 3z + 2 × 3z × 2x

➭ 4x² + y² + 9z² + 4xy + 6yz + 12xz

∴ The answer of this question is

4x² + y² + 9z² + 4xy + 6yz + 12xz

Formula used :-

➪ (a + b + c)²

➭ a² + b² + c² + 2ab + 2bc + 2ca

2) (102)³

➭ (100 + 2)³

➭ (100)³ + (2)³ + 3 × 100 × 2 × (100 + 2)

➭ 1000000 + 8 + 600 × (102)

➭ 1000000 + 8 + 61200

➭ 1061208

∴ The answer of this question is 1061208

Formula used :-

➪ (a + b)³

➭ a³ + b³ + 3ab(a + b)

3) (3a + 4b)³

➭ (3a)³ + 3 × (3a)² × (4b) + 3 × (3a) × (4b)² + (4b)³

➭ 27a³ + 108a²b + 144ab² + 64b³

∴ The answer of this question is

27a³ + 108a²b + 144ab² + 64b³

Formula used :-

➪ (a + b)³

➭ a³ + 3a²b + 3ab² + b³