Question

12. f(x)= ax4 + bx2 + x + 5, f(-3)=2 what is the value of f(3)?

Answer 1

$given \\ f(x) = a {x}^{4} + b {x}^{2} + x + 5 \\ f( - 3) = 2 \\ i.e. \: a {( - 3)}^{4} + b {( - 3)}^{2} - 3 + 5 = 2 \\ 81a + 9b = 0 \\ \\ f( 3) = a {( 3)}^{4} + b {( 3)}^{2} + 3 + 5 \\ = 81a + 9b + 8 = 0 + 8 = 8$

Answer 2

Question :-

f(x) = ax⁴ +bx²+x +5 ,f(-3) = 2 then find the value of f(3) ...?

Answer :-

→ f(3) = 8

To find :-

→ value of f(3)

Explanation :-

Given that ,

→ f(x) = ax⁴ +bx² +x + 5

According to the question,

f(-3) = 5

→ a(-3)⁴ +b (-3)² -3 +5 = 2

→81a + 9b = 0 .....eq.(1)

Now ,

→ f(3) = a(3)⁴+b(3)²+3+5

→ f(3) = 81a +9b +8

from eq.(1)

→ f(3) = 0+8

→ f(3) = 8

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