Question

12. Factorise the term 8(3a-2b)^2 - 10 (3a-2b) is

2(3a - 2b) (12a - 8b - 5)
2(3a + 2b) (12a - 8b -5 )
2(3a-2b) (12a+86-5)
None of these

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Answer 1

Answer:

sorry can't help with it

Answer 2

Answer:

2(3a - 2b) (12a - 8b - 5)

Step-by-step explanation:-

The factorisation of 8 - 10(3a - 2b) = 2(3a - 2b)(12a - 8b - 5)

Step-by-step explanation:

We have,

8 - 10(3a - 2b)

To find, the factorisation of 8 - 10(3a - 2b) = ?

∴ 8 - 10(3a - 2b)

= (2 × 4) - (2 × 5) (3a - 2b)

Taking 2(3a - 2b) as common, we get

= 2(3a - 2b)[4(3a - 2b) - 5]

= 2(3a - 2b)(12a - 8b - 5)

∴ The factorisation of 8 - 10(3a - 2b) = 2(3a - 2b)(12a - 8b - 5)