Question

12. Find four different solutions for each of the following equation:
(1) 2x + y = 5 (2) x = 5y (3) 3(x-1)=2(y+3)+3​

Answer 1

Answer:

Given equation is:

2x+y=7

For x = - 1, we get

−2+y=7

⇒y=9

∴ (-1, 9) is a solution.

For x = 0, we get

⇒0+y=7

⇒y=7

∴ (0, 7) is a solution.

For x = 1, we get

⇒2+y=7

⇒y=5

∴ (1, 5) is a solution.

For x = 2, we get

⇒4+y=7

⇒y=3

∴ (2, 3) is a solution.

Hence, we have four solution (−1,9),(0,7),(1,5)and(2,3)