Question

12. Find out the Eºcol from the given data
(a) Zn | Zn+2 || Cut2 | Cu; Eºcell = 1.10 V
(b) Cu Cu 2 || Agt | Ag : Eºcell = 0.46 V
(c) Zn | Zn+2 || Agt | Ag; Eºcell = ?
(Given Ecout2/c = 0.34V)
(1) - 0.04 V
(2) +0.04 V
(3) + 0.30 V
(4) 1.56 V​

Answer 1

Answer:

Explanation:

Enot cell = Enot op + Enot rp

where op is oxidation potential

and rp is reduction potential

for first cell

Enot cell = Enot op + Enot rp

1.10 = 0.34 + Enot op

0.76 = Enot op

for second cell

Enot cell = Enot op + Enot rp

note Enot op = -Enot rp

except for h2o

from above statement

Enot op of cu = - Enot rp of cu

Enot op of cu = - 0.34

Enot cell = Enot op + Enot rp

0.46 = -0.34 + x

0.80 = x

we have found

Enot op of zn = 0.76

Enot rp of ag = 0.80

for third cell

Enot cell = Enot op + Enot rp

Enot cell = 1.56

Answer 2

Explanation:

1.10 = RHS - LHS

-1.10 = -0.34 + Zn/Zn+2

= - 0.76

0.46 = Ag+/Ag - LHS

0.46 = RHS - (- 0.34)

Ag+/Ag = 0.46 + 0.34

= 0.8

e.m.f = RHS- LHS

= 0.8 - ( - 0.76)

= 1.56v