Question

12. Find product
(5x² -2y +7) (4x - 1)​

Answer 1

Answer:

Change x to(x-1) in the above function f(x)

Then we get f(x-1)=3(x-1)^4–5(x-1)^2+9

Use the formulas

(x-1)^4= x^4–4x^3+6x^2–4x+1

And (x-1)^2=x^2–2x+1

On substituting in the above function we get

f(x-1)=3(x-1)^4–5(x-1)^2+9

f(x-1)=3(x^4–4x^3+6x^2–4x+1)-5(x^2–2x+1)+9

So the function becomes

f(x-1)=3x^4–12x^3+13x^2–2x+7

This is the required solution.

Step-by-step explanation:

hope it helps you mark me BRANLIST and give thanks please

Answer 2

Answer:

20x3−5x2−8xy+28x+2y−7

Step-by-step explanation:

(5x2−2y+7)(4x−1)

=(5x2+−2y+7)(4x+−1)

=(5x2)(4x)+(5x2)(−1)+(−2y)(4x)+(−2y)(−1)+(7)(4x)+(7)(−1)

=20x3−5x2−8xy+2y+28x−7

=20x3−5x2−8xy+28x+2y−7