Question

12. Find the area of a rectangular park whose length and breadth are 15 2/3 m and 11 1/2 m , respectively ​

Answer 1

Given

• Length of rectangle = 15 ⅔ m
• Breadth of rectangle = 11 ½ m

Find out

• Area of rectangle

Solution

As we know that

★ Area of rectangle ★

➟ Length × breadth

➟ 15 ⅔ × 11 ½

➟ 47/3 × 23/2

➟ 1081/6

➟ 180.16 m²

Hence,

• Area of rectangle is 180.16 m²

Additional Information

• Area of circle = πr²

• Circumference of circle = 2πr

• Perimeter of rectangle =2(l + b)

• Perimeter of square = 4 × side

• Area of square = side × side

• Area of rhombus = ½ × product of diagonals

• Area of Parallelogram = base × height

• Area of trapezium = ½ × sum of parallel sides × height

$\rule{200}3$

Answer 2

✤ Given ✤

$\bullet\ \sf{Length\ of\ a\ rectangular\ park=15\dfrac{2}{3}\ m }\\\\\bullet\ \sf{Breadth\ of\ the\ rectangular\ park=11\dfrac{1}{2}\ m }$

✤ To Find ✤

$\sf{The\ area\ of\ the\ rectangular\ park.}$

✤ Solution ✤

$\sf{We\ know,\ for\ a\ rectangle,}$

$\boxed{\sf{\color{magenta}{Area=Length \times Breadth}}}$

$\textsf{Substituting the values :-}$

$\sf{\longrightarrow A=15\dfrac{2}{3}\times11\dfrac{1}{2} }\\\\\sf{\longrightarrow A=\dfrac{(3\times15)+2}{3}\times \dfrac{(2\times11)+1}{2} }\\\\\sf{\longrightarrow A=\dfrac{45+2}{3} \times \dfrac{22+1}{2}}\\\\\sf{\longrightarrow A=\dfrac{47}{3} \times \dfrac{23}{2}}\\\\\sf{\longrightarrow A=\dfrac{1081}{6} }\\\\\boxed{\boxed{ \color{lime}{\sf{\longrightarrow A= 180\dfrac{1}{6}\ m^2}}}}$

$\mathbf{Hence,\ the\ area\ of\ the\ rectangular }\\\mathbf{\ park\ is\ 180\dfrac{1}{6}\ m^2.}$