Question

12. Find the area of a square whose perimeter is 9 1/11m.​

Answer 1

Answer :-

• The area of the square is 625/121 m.

To find :-

• The area of a square whose perimeter is 9 1/11 m.

Solution :-

• Before finding the area of the square, we have to find the length of it's side.

We know that :-

$\underline{ \boxed{\sf Perimeter \: of \: a \: square = 4 \times Side}}$

Here,

• Perimeter = 9 1/11 m.

Let :-

• The side of the square be "x" m.

Then,

$\longmapsto\tt 9\dfrac{1}{11} = 4 \times x$

$\longmapsto\tt \dfrac{100}{11} = 4 \times x$

$\longmapsto\tt \dfrac{100}{11} \div 4 = x$

$\longmapsto\tt\dfrac{100}{11} \times \dfrac{1}{4} = x$

Cancelling the numbers,

$\longmapsto\tt\dfrac{25}{11} \times \dfrac{1}{1} = x$

$\longmapsto\tt\dfrac{25}{11} \: m = x$

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• Now, let's find the area of the square!

We know that :-

$\underline{ \boxed{ \sf Area \: of \: a \: square = Side \times Side}}$

Here,

• Side = 25/11 m.

Therefore,

$\longmapsto\tt Area = \dfrac{25}{11} \times \dfrac{25}{11}$

$\longmapsto\tt Area = \dfrac{625}{121} \: m$

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Hence :-

• The area of the square is 625/121 m.