Question

12. Find the area of the equilateral triangle whose
each side is (m) 12 cm (in) 5 cm,​

Answer 1

Answer:

As the formula of area of eq. triangle is = ➡

$\huge \frac{ \sqrt{3} }{4} \: \times {side}^{2}$

NOW:-

i)

side =12cm

$area \: of \: \triangle \: = \: \frac{ \sqrt{3} }{4} \times {12}^{2} \\ = \frac{ \sqrt{3} }{ \cancel{4}} \times 12 \times \cancel{12} \\ = 12 \sqrt{3} {cm}^{2} \\ = 20.78 {cm}^{2}</p><p>$

ii)

side = 5 cm

$area \: of \: \triangle \: = \frac{ \sqrt{3} }{4} \times {5}^{2} \\ = \frac{ \sqrt{3} }{4} \times 5 \times 5 \\ = \frac{25 \sqrt{3} }{4} {cm}^{2} \\ = 10.82 {cm}^{2}$