Question

12. Find the interior angles of a decagon which are given as (3x +10)".(2x + 7) (4x-3).(5x-2).(2x+15),(3x + 2), (x+ 3l.(2x+5),(3x-1) and (3x4)​

Answer 1

Answer:

The interior angles of a decagon are given as (3x+10)°.(2x + 7)º. (4x - 3)º(5x-2)°(2x+15) (3x + 2), (x+3)(2x+5), (3x - 1)º and (3x + 4)º.

answer

plzz mark as brainlist

Answer 2

Step-by-step explanation:

Sum of all interior angles of a polygon = (n - 2)×180

(3x +10) + (2x + 7) + (4x-3) + (5x-2) + (2x+15) + (3x + 2) + (x+ 3) + (2x+5) + (3x-1) + (3x+ 4) = (10 - 2) × 180

28x + 40 = 2440

28x = 1400

x = 20

So angles are 70, 47, 77, 98, 55, 62, 23, 45, 59, 64