12. Find the length of a diagonal of a quadrilateral, if the area of the quadrilateral is 70 sq cm and the perpendiculars to the diagonal from the opposite vertices are of length 6 cm and 8 cm.
Answers
Let, B can do the work in x days
∴ Part of work B can do in a day = 1/x
A can do a piece of work in 60 days
∴ Part of work A can do in a day = 1/60
He works alone for 12 days and then B finished it in 24 days
∴ 12/60 + 24/x = 1
∴ 24/x = 1 – (1/5)
⇒ 24/x = 4/5
⇒ 1/x = 1/30
Part of work together they can do the work in a day
= 3/60
= 1/20
∴ They can do the work together in 20 days
Step-by-step explanation:
Let, B can do the work in x days
∴ Part of work B can do in a day = 1/x
A can do a piece of work in 60 days
∴ Part of work A can do in a day = 1/60
He works alone for 12 days and then B finished it in 24 days
∴ 12/60 + 24/x = 1
∴ 24/x = 1 – (1/5)
⇒ 24/x = 4/5
⇒ 1/x = 1/30
Part of work together they can do the work in a day
= 3/60
= 1/20
∴ They can do the work together in 20 days
Answer:
Diagonal of a quadrilateral can be found by using the pythagoras theoram.
Step-by-step explanation:
Length = 8 cm
Breadth = 6 cm
Applying pythagoras theoram :
AC^2 = AB^2+BC^2
AC^2 = (6)^2+(8)^2
AC^2 = 36+64
AC^2 = 100
AC = Square root (100)
AC = 10 cm