Question

12.find the perimeter of the rectangle whose length 15 cm and width is of 8 cm​

Answer 1

Perimeter of rectangle = 2(l+b)

so,

2(15+8)

2× 13

16cm

so perimeter of rectangle = 16cm

Answer 2

Answer:

$\huge\underline\mathfrak\red{question}$

find the perimeter of a triangle whose length 15 cm and wide is 8 cm

$\underline\mathfrak\blue{solution}$

==>> 46cm

let's find out!!

perimeter of rectangle is 2(l+b)

we have:-

• length is 15cm
• width is 8cm

so,

==>> 2(15+8)

==>> 2(23)

==>> 46

hence the perimeter of rectangle is 46cm.