Question

12. Find the ratio of the number of molecules contained in 1 g of NH, and 1 g of N2?​

Answer 1

Answer:

$\huge\blue{Answer:-}$

1 gram N2 number of molecules = (6.023*1023)/28

Now the ration of number of molecules between NH3 and N2 = [(6.023*1023)/17]/[(6.023*1023)/28]

= 28/17

So their ration of molecules contained is 28/17.

Explanation:

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Answer 2

Answer:

In 1 gram N2 number of molecules = (6.023*1023)/28

Now the ration of number of molecules between NH3 and N2

= [(6.023*1023)/17]/[(6.023*1023)/28]

= 28/17

So their ration of molecules contained is 28/17.