Question

12. Find the remainder obtained on dividing p(x) =x+3x²+3x+1 by x+1
OR​

Answer 1

$x + 1 = 0$

$x = -1$

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$p(x) = 3x^2 +4x +1$

$p(-1) = 3×(-1)^2 +4×(-1) +1$

$=> 3-4+1$

$=> -1+1$

$=> 0$

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Hence,$\fbox{Remainder => 0}$

Answer 2

ANSWER :-

x + 1 = 0

x = -1x=−1

___________

p(x) = 3x² +4x +1

p(-1) = 3×(-1)² +4×(-1) +1

=> 3-4+1

=> -1+1

=> 0

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Hence,$\fbox{Remainder => 0}$