Math, asked by neha8529, 11 months ago

12. Find the smallest square number divisible
by each one of the numbers 8, 9 and 10.

Answers

Answered by jainsid131
2

Answer: 3600 = 2^4 x 3^2 x 5^2

Answered by lebazir2004
7

Answer: 3600

Step-by-step explanation:L.C.M. of 8,9,10 is 2*2*2*3*3*5=360

Since 2 and 5 are not in pairs multiply by 2 and 5 to make it a perfect square.

The required number=360*2*5=3600

The smallest square number divisible by 8,9,10=3600. 

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