12. Find the sum of the angles angle DAB + angle ABD + angle ADB + angle BDC + angle DCB + angle DBC.
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Answer:
Opposite angles of parallelogram are equal.
∠DAB=∠BCD=75
o
and ∠DBC=60
o
∠BDC+∠DBC+∠BCD=180
o
∠BDC=180
o
−∠DBC−∠BCD=180
o
−75
o
−60
o
=45
o
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