Question

12, Find the sum of the first 40 positive integers divisible by 6.
​

Answer 1

Answer:

12,18,24,30,36,42,48,54,60,66,72,78,84,90,96,102,108,114,120,126,132,138,144,150,156,162,168,174,180,186,192,198,204,210,216,

Answer 2

492

Step-by-step explanation:

d = 6

a = 6

n = 40

an = ?

Sn = ?

now;

an = a + (n-1)d

an = 6 + (40 - 1) 6

Sn = n/2 [2a + (n -1 )d]

Sn = 40/2 [2×6 + (40 - 1)6]

Sn = 20 (12+234)

Sn = 20 × 246

Sn = 492

please mark mea s brainlist