Question

12. Find the total surface area of a closed cylinder whose radius is 21 cm and height 5 cm.​

Answer 1

Answer:

r= 21cm and h=5cm

TSA of closed cylinder = 2πr(r+h)

=2×22/7 ×21×(21+5)

=2×22×3×26=3432cm²

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Answer 2

In context to questions asked,

We have to determine the value of total surface area of cylinder.

As per questions,

It is given that,

radius = 21 cm

Height = 5 cm

As we know that,

Total surface area of closed cylinder is = 2πr(h+r)

So, putting the value of given terms in above equation,

We will get,

$2πr(h+r) = 2 \times \frac{22}{7} \times 21 \times (21 + 5) \\ = > 2 \times \frac{22}{7} \times 21 \times 26 \\ = > 2 \times 22 \times 3 \times 26 \\ = > 3432 \: {cm}^{2}$

Hence, total surface area of closed cylinder will be 3432 sq. cm