Question

12. find the value of a and b
so that p(x) = x^3-3x^2-ax+b bas factors as x+1 and x-5 as factors.
Cllass 9 with steps

Answer 1

Step-by-step explanation:

(x+1)³-3(x+1)²-a(x+1)=0

x³+1+3x-3x²+3+6-ax-a+b=0

just put x-5

in in this equation and simplify them and at last use have to equal them u get a and b value perfectly