Question

12 Find the value of k for which the roots of the quadratic equation
(k-4)x2+2(k-4)x+2=0 are equal.​

Answer 1

AnSweR

if both the roots are equal ;

then discriminant

$= = > \: {b}^{2} = 4ac$

a = k-4 ; b = 2(k-4) ; c = 2 ; substituting the values

${(2k - 8)}^{2} = 4 \times (k - 4) \times 2 \\ \\ {4k}^{2} + 64 - 32k = 8k - 32 \\ \\ {4k}^{2} - 40k + 96 = 0 \\ \\ {k}^{2} - 10k + 24 = 0 \\ \\ (k - 4)(k - 6) = 0$

K = 4 ,6

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