12) Find the value of k if (-2)^ K+1 ×(2)=(-2)7
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It is given that 4x−3y+1=0
Now by substituting the value of x and y in the equation
4(3k+2)−3(2k−1)+1=0
On further calculation
12k+8−6k+3+1=0
6k+12=0
So we get
6k=−12
By division
k=−2
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