Question

12. find the value of x in each case..
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Answer 1

Answer:

1. ∠SPT = QPR = 40°

∠QPR = 40° (Verically Opposite Angle)

2. ∠PRQ + ∠PRO = 180 (Linear Pair)

   ∠PRQ + 125° = 180

   ∠PRQ = 180° - 125°

   ∠PRQ = 55°

3. ∠QPR + ∠PRQ + PQR = 180°  (Sum of All angles of Δ is 180°)

    40° + 55° + ∠PQR = 180°

    ∠PQR = 180° - 95°

    x = ∠PQR = 85°

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1. ∠C + 91° = 180° (Linear Pair)

∠C = 180° - 91°

∠C = 89°

2. ∠B = 46° (Alteranate Interior Angle)

3. 91° + 46° + ∠X = 180 (Sum of all angles of Δ is 180°)

    ∠X = 180° - 137

    ∠X = 43°