12. Find the zeroes of the polynomial :
p(x) = (x - 2)^2 - (x + 2)^2
Answers
Answered by
2
Step-by-step explanation:
p(X)=0
x^2-4x+4-(x^2+4x+4)
-8x=0
X=o and X=0
Answered by
0
Step-by-step explanation:
=(x^2-2X2+2^2)-(x^2+2X2+2^2)=0
=(x^2-4x+4)-(x^2+4x+4)=0
=x^2-4x+4-x^2-4x-4=0
= -8x=0
=x=0/-8
=x=0. ,x=0.
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