Question

12) find
the zeroes of the quadratic polynomial
6n² - 3-7n and verify the
relation between
the
and the
the
polynomial.
zero es
coefficient of the polynomial​

Answer 1

Answer:

6n² -3-7n

6n²-7n-3. sum=-7 product =-18

No.=-9,2

(6n²+2n)(-9n-3)

2n(3n+1)-3(3n+1)

(2n-3)(3n+1)

n=3/2, n= -1/3

α=3/2, β=-1/3

α+β=-b/a=7/6

α+β =3/2+-1/3=9-2

6

=7/6

αβ=c/a =-3/6= -1/2

αβ=3/2×-1/3

=-3/6

=-1/2

relationship is varified

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