Question

12-Find the zeroes of the quadratic
polynomial 6x^2-3 - 7x. Verify the
relationship between the zeroes and the
coefficients.​

Answer 1

Step-by-step explanation:

Given that p(x) = 6x²-7x-3

We shall find zeroes by middle term splitting

6x²+2x-9x-3

2x(3x+1)-3(3x+1)

(2x-3)(3x+1)

Therefore zeroes are 3/2 and - 1/3.

Verification

P(x) 6x²-7x-3

A = 6 ; b = - 7 ; c = - 3

Sum of zeroes = - b/a

3/2 + (-1/3) = 7/6

9/6 + - 2/6 = 7/6

Product of zeroes = c/a

3/2 * - 1/3 =. - 3/6

-1/2 = - 1/2