Question

12. Find the zeroes of the quadratic polynomial x2 +7x+10 and verify the relationship between
the zeroes and its co-efficients.

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Answer 1

Answer:

Step-by-step explanation:

$let p(x) = x^2 + 7x + 10 \\= (x^2 + 5x) + (2x +10) \\= x(x +5) + 2(x + 5) \\= (x +2)(x +5)$

therefore, the zeroes are  α = (-2), β  = (-5)

α + β = (-2) + (-5) = -7 = $\frac{- coefficient of x}{coefficient of x^2}$

αβ = (-2)(-5) = 10 = $\frac{constant term}{coefficient of x^2}$