Question

12. Four particles are at the corners of a square. Of side "a" if they move towards each other always with velocity v. The time after which they meet.
a.)a/v
b.)2a/v
c.)a/2v
d.)3a/2v​

Answer 1

Answer:

a/v√2

Explanation:

Four particles are at the corners of a square. Of side "a" if they move towards each other always with velocity v. The time after which they meet.

a.)a/v

b.)2a/v

c.)a/2v

d.)3a/2v​

Four particles are at the corners of a square so they all will meet at the intersection point of diagonals of square

Square side = a

Diagonal length = a√2

Intersection point difference from Corner = a√2/2 = a/√2

Distance to be travlled by each = a/√2

Speed of each = v

Time taken = Distance / Speed  =   (a/√2)/v   = a/v√2