Question

12 friends entered a restaurant where there are
only three tables left. One table can seat three
persons, the other can seat four and the largest
table can seat five. In how many ways can the
waiter seat the 12 friends assuming that the order
of seating at the tables is immaterial?​

Answer 1

Answer:

The 12 friends can sit in:-

3 people in the 3 seater table

4 people in the 4 seater table

5 people in the 5 seater table

3+4+5 = 12

Step-by-step explanation:

Answer 2

Answer:

The answer is 27720

Step-by-step explanation:

12 friends, 3tables and (3+4+5;) 12 seats, so everyone can seat but 1st table has 3 seats, 2nd has 4, and 3rd has 5. so we have to use combinantion as such,

*following the nCr rule*

Answer: (12C3) × [(12-3)C4] × [(12-3-4)C5]

so simplified as 12C3 × 9C4 × 5C5

which is 27720.

the number drops from 12 to 9 to 5 as the other friends have already been seated in the other term, so the total number of people unseated drops gradually. Hope this helped