Physics, asked by shibanipradhan04, 5 months ago

12. From a rifle of mass 5 kg, a bullet of mass 20g
is fired with an initial velocity of
30 m/s. The initial velocity of recoil of the rifle is:
0 -0.3 m/s
0 -0.6 m/s
0 -0.9 m/s
0 -0.12 m/s​

Answers

Answered by byritesh7483
3

Explanation:

Explanation:as we know

Explanation:as we knowm1*v1=m2*v2

where,

m1=mass of gun

v2=recoil velocity of gun

m2=mass of bullet

v2=velocity of bullet

act formula

5*v1=30*20/1000

v1=0.6/5

v1=0.12m/s

as the direction of recoil velocity is oppostive therefore, velocity of gun is. -0.12m/s

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