12. From the top of a 7 m high building, the angle of elevation of the top of a cable tower is
60° and the angle of depression of its foot is 45º. Determine the height of the tower.
Answers
Answered by
3
In ΔABE,
tan60
o
=
AB
h
h=AB
3
....(i)
In ΔABC,
tan45
o
=
AB
7
AB=7 ...(ii)
By equation (i) and equation (ii)
h=7
3
So, height of tower is =h+7=7(
3
+1)
Answered by
2
Answer:
Step-by-step explanation:
In ΔABE,
tan60
o
=
AB
h
h=AB
3
....(i)
In ΔABC,
tan45
o
=
AB
7
AB=7 ...(ii)
By equation (i) and equation (ii)
h=7
3
So, height of tower is =h+7=7(
3
+1)
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