12 g mg (at mass 24 ) react with dilute mineral acid to produce maximum hydrogen equal to
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Answer:
Mg + 2 H{+} → Mg{2+} + H2
Supposing the question to be "How much hydrogen is produced?":
(12 g Mg) / (24.30506 g Mg/mol) x (1 mol H2 / 1 mol Mg) = 0.49 mol H2
(0.49 mol H2) x (22.414 L/mol) = 11 L H2 at STP
(0.49 mol H2) x (2.015894 g H2/mol) = 0.99 g H2
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Answered by
3
Answer:
Mg + 2 H{+} → Mg{2+} + H2
Supposing the question to be "How much hydrogen is produced?":
(12 g Mg) / (24.30506 g Mg/mol) x (1 mol H2 / 1 mol Mg) = 0.49 mol H2
(0.49 mol H2) x (22.414 L/mol) = 11 L H2 at STP
(0.49 mol H2) x (2.015894 g H2/mol) = 0.99 g H2
Explanation:
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