12 g of saturated solution of potassium chloride at 200 C when evaporated to dryness leaves a solid residue of 3 g. Calculate the solubility of KCl.
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Explanation:
Weight of Water in solution = 12g - 3g = 9g
9g of H2O dissolves 3g of solid
=> 100g of Water will dissolve
(3/9)X100 = 33.3g
=> Solubility of Potassium Chloride(KCl) at 20 degrees Celsius in H2O = 33.3g.
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