Question

12. Given that sin 0 = a\b

then cos 0 is equal to

Answer 1

Answer:Answer:

cos\theta =\frac{\sqrt{(b^{2}-a^{2})}}{b}

Step-by-step explanation:

Given sin\theta = \frac{a}{b} ---(1)

We know the Trigonometric identity:

\boxed {cos^{2}\theta=1-sin^{2}\theta}

Now ,

cos\theta = \sqrt{1-sin^{2}\theta}

= \sqrt{1-\left(\frac{a}{b}\right)^{2}}

\* From (1)*\

= \sqrt{\frac{b^{2}-a^{2}}{b^{2}}}

= \frac{\sqrt{(b^{2}-a^{2})}}{b}

Therefore,

cos\theta =\frac{\sqrt{(b^{2}-a^{2})}}{b}

Explanation: