Question

12% glucose solution is prepared by dissolving 50 g of glucose in water. The amount of water required
is :
(A) 360.33 g \B
(B) 366.67 g
(C) 364.33 g
(D) 367.67 g
5. 20/g of acetic acid is dissolved in 250 ml of water. The concentration of the acid solution is :​

Answer 1

Answer:

Molality is defined as the number of moles of solute per kilogram of solvent.

Number of moles of solute is n=

M

m

=

180

x

Weight of solvent is 50/1000=0.05 Kg

Given molality is 0.3 M.

0.3=

0.05

(

180

x

)

⇒x=180×0.05×0.3=2.7 g

Hence, option C is correct.

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