12 gram of acitic acid is present in 250 ml of solution calculate M and N
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Answer:
Explanation:
M=n/v(l)
Or M=wt/gmw×1000/v(ml)
M=12/60×1000/250
M=4/5
N=M×n where n= n-factor
n-factor for acetic acid=1since no h+ released is 1
Therefore N=4/5×1
N=4/5=0.8
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