Question

12 gram of acitic acid is present in 250 ml of solution calculate M and N​

Answer 1

Answer:

Explanation:

M=n/v(l)

Or M=wt/gmw×1000/v(ml)

M=12/60×1000/250

M=4/5

N=M×n where n= n-factor

n-factor for acetic acid=1since no h+ released is 1

Therefore N=4/5×1

N=4/5=0.8